Answers: Ch 3 Tissues In Action Class 9 [Exploration] NCERT

“Answers: Ch 3 Tissues In Action Class 9 [Exploration] NCERT textbook is prepared solely based on the NCERT textbook for grade 9. We have not used any reference books to prepare the solutions.

We have also mentioned the exact page, paragraph, and line numbers from the chapter where each answer is taken from.

This way, you’ll know exactly where each question comes from.

There are 15 questions in total in the Revise, Reflect, Refine section. Some questions have subparts.

First, make sure to read the chapter thoroughly. Then, prepare the short notes for Chapter 3, “Tissues in Action.”

Finally, you should now try solving the end-of-chapter questions titled “Revise, Reflect, Refine.”

Click on the Table of Contents to go directly to the desired question.

Happy solving!

Table of Contents

Revise, Reflect, Refine
Answers

Q1.

Meristematic tissues divide repeatedly. What property of their cells allows them to do this?

(i) They have thick walls for protection.
(ii) They contain large vacuoles that store nutrients.
(iii) They have thin walls, dense cytoplasm, and a large, prominent nucleus.
(iv) They are functionally differentiated cells.

(iii) They have thin walls, dense cytoplasm, and a large, prominent nucleus.

Q2.

If a plant is unable to transport food from leaves to roots, which tissue
is malfunctioning?

(i) Xylem
(ii) Phloem
(iii) Epidermis
(iv) Sclerenchyma

(ii) Phloem

Q3.

Why are the epithelial tissues that line an animal’s internal organs
usually only one or a few cells thick?

(i)
To store food efficiently.
(ii) To provide maximum strength.
(iii) To allow quick exchange of materials across them.
(iv) To reduce friction.

(iii) To allow quick exchange of materials across them.

Q4.

You can perform these two jumps (Fig. 3.21):

Straight-leg jump — keep knees and ankles stiff.
Normal jump — bend knees and ankles naturally.
How did your ankle, knee, and hip positions differ between the two
jumps?

In the straight-leg jump, knees and ankles are kept stiff. There is no bending at these joints. The body lands with a jolt as there is no cushioning.

In the normal jump, knees and ankles bend naturally. This bending absorbs the impact of landing.

Q5.

Which type of joint is involved when you bend your knees and ankles?

(i) Ball and socket
(ii) Hinge
(iii) Pivot

(ii) Hinge

The knee and ankle both work like hinges, bending in one direction only.

Q6.

In each of the following cases (A, B, C, and D), choose the correct option
as given below:

(i) Both (A) and (R) are true, and (R) is the correct explanation of (A).
(ii) Both (A) and (R) are true, but (R) is not the correct explanation
of (A).
(iii) (A) is true, but (R) is false.
(iv) (A) is false, but (R) is true.


(A)
Assertion: Epithelium is well-suited for gas exchange in the lungs.
Reason: It consists of multiple layers of tall cells that slow down
diffusion.

(B)
Assertion: Cardiac muscle can contract continuously without
fatigue.
Reason: Cardiac muscle cells have a high number of mitochondria
and an abundant blood supply.

(C)
Assertion
: Tendons connect bone to bone and allow joint movement.
Reason: Tendons are made of tough connective tissue that transmits
force from muscle to bone.

(D)
Assertion
: In a hinge joint, movement occurs primarily in one
plane.
Reason: The bone ends are shaped to allow sliding in all directions.

A| Answer: (iii) (A) is true, but (R) is false.

B| Answer: (i) Both (A) and (R) are true, and (R) is the correct explanation of (A).

C| Answer: (iv) (A) is false, but (R) is true.

The reason explains why — high mitochondria provide constant energy, and a rich blood supply delivers oxygen continuously, making non-stop contraction possible.

Tendons connect muscle to bone — NOT bone to bone. Ligaments connect bone to bone. The reason is correct, but the assertion is wrong.

D| Answer: (iii) (A) is true, but (R) is false.

A hinge joint does move in only one plane — the assertion is correct. But the reason is false. Hinge joints do NOT allow sliding in all directions. That is why movement is limited to one direction.

Plot a graph between the age of a tree (in years) on the x-axis and the
diameter of the tree (in cm) along with the number of annual rings
formed over time on the y-axis, using the data given in Table 3.7.

(i) Analyse the graph in terms of the diameter of the stem over time
and share the interpretation.
(ii) What is the relation between the diameter of the teak tree to the
Annual rings formed?
(iii) Which specialised tissue is responsible for the girth of the stem
And where is it located?

(i) Answer: As the age of the tree increases, the diameter of the stem also increases. The growth is not perfectly even — there is a sharper increase between years 10 and 20 (from 8 cm to 24 cm). After year 20, growth becomes more gradual. Overall, older trees have wider stems.

(ii) Answer: The number of annual rings equals the age of the tree in years. As the diameter increases, the number of annual rings also increases. Each year, one new ring is added. So, more rings mean a greater diameter.

(iii)Answer: The lateral meristem is responsible for the increase in girth of the stem.

Source: Page 31, Section 3.2.2 “The increase in girth occurs due to the presence of actively dividing cells arranged in a ring in the stem. These cells divide and produce new cells inside and outside in a concentric manner, leading to an increase in the diameter of the stem. This meristematic tissue is called the lateral meristem.”

It is located along the circumference (ring) of the stem.

In a forest, it was observed that one of the trees was severely debarked by an elephant to meet its food requirements, as the bark is a rich source of nutrients (Fig. 3.22). Based on your learning, answer the following:


(i) Which function(s) of the tree is/are hampered by debarking?

(ii) Which plant tissue would be affected by further damage to the tree trunk even after debarking?

(iii) Which function of the tree would be hampered if the tissues beneath the bark were severely damaged?

(iv) What assumptions are you making to answer the questions above? How would the answer change if your assumptions are also changed?

(i) Answer: The bark contains the epidermis (protective tissue). Removing it hampers:

  1. Reduction of water loss
  2. Protection from mechanical injury
  3. Protection from harmful microorganisms

(ii) Answer: Further damage would affect the lateral meristem, xylem, and phloem tissues lying below the bark.

(iii) Answer: If the lateral meristem is damaged, the tree will stop growing in girth. If xylem is damaged, water and minerals cannot travel from roots to leaves. If phloem is damaged, food cannot travel from leaves to other parts.

(iv) Answer:

Assumption 1: The bark contains only the epidermis and cork tissue. If the bark is thicker and includes phloem, then debarking would also disrupt food transport immediately.

Assumption 2: The inner vascular tissues (xylem and phloem) are undamaged after debarking. If they are also damaged, then both water transport and food transport would stop, and the tree may die.

Assumption 3: The tree is a mature dicot with a well-developed lateral meristem. If it is a young plant, the extent of damage and regeneration capacity would differ.

Q9.

Aamrapali observed that a young mango sapling’s stem bends flexibly
during monsoon winds and does not break. Which tissue is responsible
for this flexibility? Predict and provide your explanation of the impact
if the existing tissue was replaced by sclerenchyma.

Answer: The tissue responsible for flexibility is collenchyma.

If collenchyma were replaced by sclerenchyma:
The stem would become hard and rigid. It would not bend during strong winds. Instead, it would snap or break easily.

Q10.

Sohan designed an experiment for the regeneration of sugarcane, where he
used cuttings to grow sugarcane. He used two types of cuttings, type ‘A’ and type ‘B’ (Fig. 3.23). After a few weeks, type ‘B’ cuttings sprouted and developed into sugarcane plants, whereas the type ‘A’ cuttings did not sprout.



(i) Why were the type ‘B’ cuttings able to grow as sugarcane but type ‘A’ could
not?
(ii) What difference was present in type ‘B’ compared to type ‘A’?
(iii) What observation or measurement was made to determine whether this change had an effect?
(iv) What parameters should be kept the same for both types of cuttings to ensure a fair comparison?

(i) Answer: Type B cuttings likely contained a node with intercalary meristem. This meristematic tissue has actively dividing cells that allow the plant to regenerate and sprout.

Type A cuttings probably had no node, so no meristematic tissue was present to allow growth.

(ii) Answer: Type B cuttings had a node (the point on the stem where branches or leaves arise), which contains the intercalary meristem. Type A cuttings had no node — only the internode (the part of the stem between two nodes).

(iii) Answer: The observation made was whether the cuttings sprouted and developed into new plants after a few weeks. Type B showed new shoots growing, while Type A showed no sprouting.

This observation proved that the presence of a node (with meristematic cells) is essential for regeneration.

(iv) Answer: The following should be kept the same for both:

  1. Same length of cuttings
  2. Same soil type and pot size
  3. The same amount of water is given
  4. Same sunlight and temperature conditions
  5. Same time period of observation
  6. Cuttings taken from the same sugarcane plant

This ensures that the only variable being tested is the presence or absence of a node.

Q11.

During the discussion in class, Rohan gives a statement that, “A tissue
is a group of similar cells performing similar functions”. But Rajiv
counter argues that, “this is true in case of simple tissues but little
different in case of complex tissues”. Provide your explanation in view
of the discussion in class.

Rohan is partially correct. His definition fits simple tissues well.
Simple tissues like parenchyma, collenchyma, and sclerenchyma are made of only one type of cell, all performing similar functions.

Complex tissues like xylem and phloem are made of more than one type of cell, all working together for one function.

So Rajiv is correct — in complex tissues, different types of cells work together for a common function. The cells are not all similar, but the tissue as a whole still performs one job.

Q12.

Coconut husk fibres are used for mats which are tough and fibrous.
Which tissue has structural features suitable for providing this
strength? Explain why living parenchyma couldn’t serve the same
purpose

Sclerenchyma is the tissue responsible for the toughness of coconut husk fibres.

Why parenchyma cannot serve the same purpose: Parenchyma cells have thin walls and are loosely packed with intercellular spaces. They are living, soft, and used mainly for food storage — not for structural strength.

Source: Page 32, Section 3.2.4 (ii) a “Parenchyma consists of living cells with thin walls. These cells are loosely packed with intercellular spaces.”

Q13.

Vibha claims to her friend Neha that, “Meristematic cells are located
only at the root and shoot apices”. What do you think about this
statement? What question can Neha ask Vibha to help her understand
further if the statement is incorrect?

Vibha’s statement is incorrect. Meristematic cells are found in THREE locations, not just at the tips.

  1. Apical meristem — at root and shoot tips (what Vibha mentioned)
  2. Lateral meristem — along the circumference of stems (increases girth)
  3. Intercalary meristem — at the base of internodes or just above nodes

Question: Neha can ask Vibha: “If meristematic cells are only at the tips, how does the stem of a dicot plant increase in thickness (girth) over time? And how does grass grow back after it is mowed?”

This would lead Vibha to discover the lateral meristem and the intercalary meristem.

A plant cell and an animal cell are of the same size.

(i) Which cell will have a larger vacuole? Give reasons.
(ii) What assumptions are you making to answer the question above?

(i)The plant cell will have a larger vacuole.

Plant cells generally have large, central vacuoles that store water, food, and waste materials. Animal cells either have very small vacuoles or none at all.

(ii)

  1. If the plant cell were meristematic, it would not have a larger vacuole than an animal cell.
  2. We are assuming both cells are mature (not dividing/meristematic) cells. Meristematic plant cells do not have vacuoles.
  3. We are assuming the plant cell is a typical permanent tissue cell (like parenchyma), not a specialised cell.
  4. We are assuming “same size” means total cell size, not cytoplasm size.

A textbook states, “Each plant tissue performs only one specific
function”. What questions would you ask to critically examine the
correctness of this statement? What examples of tissues would you
take to find out the answers to these questions?

This statement is not fully accurate. Some plant tissues perform more than one function.

Critical questions to ask:

  1. Does parenchyma only store food, or does it also perform photosynthesis?
  2. Does the epidermis only protect, or does it also help in gaseous exchange and transpiration?
  3. Does xylem only transport water, or does it also provide structural strength?
  4. Can sclerenchyma serve as both a supporting and a protective tissue?

Examples to test the statement:

Parenchyma — stores food AND performs photosynthesis in green parts AND in aquatic plants forms air spaces to help float.

Epidermis — protects the plant AND helps in gaseous exchange through stomata AND assists in transpiration AND root hairs absorb water.

Source: Page 32 “In leaves, the epidermis contains pores called stomata, which apart from gaseous exchange helps in transpiration.”

Xylem — transports water AND minerals AND provides strength to the plant.

Source: Page 33 “Xylem is the tissue that transports water and minerals from the roots to other parts of the plant. It also provides strength to the plant.”

Therfore, Many tissues perform more than one function.

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