Master Sound Class 9 MCQs Online Test| Quiz format

To get maxium from “Sound Class 9 MCQs Online Test” do the below 2 thigns:

  1. Read the chapter from the NCERT
  2. Prepare the short notes – Sound Class 9 Short Notes

Then practice the MCQs again and agian to have a sound grasp on the chapter.

MCQ 1.

Sound is produced due to:
A. High temperature
B. Vibrations of objects
C. Change in pressure only
D. Electric current

Answer: B
Explanation: The text clearly states that “Sound is produced by vibrating objects” .


MCQ 2.

Which of the following actions does NOT produce sound?
A. Plucking a string
B. Shaking a bell
C. Heating water
D. Rubbing a drum surface

Answer: C
Explanation: Plucking, scratching, rubbing, blowing, shaking are ways to produce sound because they cause vibration. Heating water does not create vibration that produces sound.


MCQ 3.

What happens when a vibrating tuning fork touches a suspended ping-pong ball?
A. The ball melts
B. The ball moves due to vibrations
C. The ball changes color
D. Nothing happens

Answer: B
Explanation: The vibrating tuning fork hits the suspended ball causing it to move, showing vibrations produce sound and motion.


MCQ 4

A tuning fork vibrates 350 times per second. How long does it take to complete 1 vibration?
A. 0.003 s
B. 0.00285 s
C. 0.0285 s
D. 3.5 s

Answer: B
Explanation:
Time period (T=1f=1350=0.0028570.00285,s.)(T = \frac{1}{f} = \frac{1}{350} = 0.002857 \approx 0.00285,s.)


🔊 Production of Sound
Vibrations • Tuning Forks • Frequency • Time Period
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MCQ 5.

Sound cannot travel through:
A. Solids
B. Liquids
C. Gases
D. Vacuum

Answer: D
Explanation: Sound needs a material medium (solid, liquid or gas). It cannot travel in vacuum.


MCQ 6.

In a sound wave, compressions are regions of:
A. Low pressure and high density
B. High pressure and high density
C. Low pressure and low density
D. High pressure and low density

Answer: B
Explanation: Compressions as regions of high pressure and high density.


MCQ 7.

Sound waves are classified as:
A. Transverse waves
B. Electromagnetic waves
C. Longitudinal waves
D. Both transverse and electromagnetic

Answer: C
Explanation: sound waves are longitudinal waves.


MCQ 8

The speed of sound in air is 344 m/s. A sound wave takes 0.02 s to reach a listener. What is the distance of the listener from the source?
A. 6.88 m
B. 17.2 m
C. 34.4 m
D. 68.8 m

Answer: A
Explanation:
Distance = speed × time = 344 × 0.02 = 6.88 m.


Propagation of Sound

🔊 Propagation of Sound (Medium, Compressions–Rarefactions)
How sound travels through media • Nature of compressions and rarefactions • Wave type and speed calculations
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MCQ 9.

The pitch of sound depends on:
A. Amplitude
B. Frequency
C. Speed
D. Medium

Answer: B
Explanation: Pitch is how the brain interprets frequency; higher frequency → higher pitch.


MCQ 10.

Loudness of sound depends on its:
A. Wavelength
B. Speed
C. Amplitude
D. Time period

Answer: C
Explanation: Loudness is determined by amplitude


MCQ 11

A sound wave has frequency 220 Hz and speed 440 m/s. What is its wavelength?
A. 1 m
B. 2 m
C. 0.5 m
D. 4 m

Answer: B
Explanation: Using(v=λν):(λ=440220=2,m.)Using (v = \lambda \nu): (\lambda = \frac{440}{220} = 2,m.)


MCQ 12

If the time period of a sound wave is 0.005 s, what is its frequency?
A. 50 Hz
B. 200 Hz
C. 500 Hz
D. 1000 Hz

Answer: C
Explanation:
Frequency = 1 / T = 1 / 0.005 = 200 → WRONG — correct is 1 / 0.002?
Correct calculation: 1 / 0.005 = 200 Hz, so answer is B.

🔊 Characteristics of Sound – Frequency, Wavelength, Pitch, Amplitude, Time Period
How pitch and loudness are determined • Wave calculations • Relationships between frequency, wavelength, and speed
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MCQ 13.

In which medium does sound travel fastest?
A. Air
B. Water
C. Hydrogen
D. Iron

Answer: D
Explanation: Table 11.1 in your NCERT shows speed in iron ≈ 5950 m/s, much higher than liquids or gases.


MCQ 14.

Why does sound travel faster in solids than in gases?
A. Solids are lighter
B. Solids have higher density and stronger particle interaction
C. Gases absorb sound
D. Sound cannot travel in gases

Answer: B
Explanation: Speed of sound depends on properties of the medium—solids have closely packed particles enabling faster transmission.


MCQ 15

How long will sound take to travel 1 km in water (speed = 1498 m/s)?
A. 0.66 s
B. 1.49 s
C. 0.89 s
D. 2.2 s

Answer: C
Explanation:
Time = distance/speed = 1000 / 1498 ≈ 0.89 s.

🔊 Speed of Sound in Different Media
How sound speed varies in solids, liquids, and gases • Calculating travel time
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MCQ 16.

The reflection of sound follows:
A. Only the law of refraction
B. No definite laws
C. The same laws as the reflection of light
D. A different set of laws

Answer: C
Explanation: Sound “follows the same laws of reflection as light” (equal angles and same plane).


MCQ 17.

Which of the following is necessary for sound reflection to occur?
A. A very smooth surface only
B. A surface of large size
C. Transparent surface
D. A source of light

Answer: B
Explanation: An obstacle of large size, polished or rough, is required for reflection of sound waves.


MCQ 18.

In a megaphone, sound is directed forward mainly due to:
A. Refraction of sound
B. Absorption of sound
C. Multiple reflections inside a conical tube
D. Sound amplification by electricity

Answer: C
Explanation: The tube and conical opening reflect sound successively to send it in one direction.

🔊 Reflection of Sound
Laws of reflection • Conditions for sound reflection • Applications like megaphones
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MCQ 19.

To hear a distinct echo, the time gap between original sound and reflected sound must be at least:
A. 0.01 s
B. 0.1 s
C. 1 s
D. 10 s

Answer: B
Explanation: Sensation of sound persists for 0.1 s, hence the minimum gap must be 0.1 s.


MCQ 20.

At 22°C, the minimum distance required between the source and reflecting surface to hear an echo is about:
A. 3.44 m
B. 17.2 m
C. 34.4 m
D. 172 m

Answer: B
Explanation: Total distance = 34.4 m → one-way distance = 17.2 m.


MCQ 21

An echo is heard after 3 seconds. If the speed of sound is 342 m/s, what is the distance of the reflecting surface?
A. 342 m
B. 171 m
C. 513 m
D. 256.5 m

Answer: D
Explanation:
Total distance = v × t = 342 × 3 = 1026 m
One-way distance = 1026 / 2 = 513 m

Correct answer should be: 513 m (Option C)
So the right option = C.

🔊 ECHO
Minimum time and distance for echo • Echo distance calculations
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MCQ 22.

Reverberation is caused due to:
A. Absorption of sound by air
B. Repeated reflections of sound
C. High-frequency vibrations
D. Destructive interference

Answer: B
Explanation: The persistence of sound in a hall due to repeated reflections is called reverberation.


MCQ 23.

Which of the following helps in reducing reverberation in halls?
A. Glass walls
B. Marble flooring
C. Smooth plastic panels
D. Sound-absorbent materials like fibreboard and curtains

Answer: D
Explanation: Roofs and walls are covered with sound-absorbent materials to reduce reverberation.


MCQ 24

Why are ceilings of concert halls curved?
A. To reduce echoes
B. To increase temperature
C. To allow uniform reflection of sound
D. To absorb sound waves

Answer: C
Explanation: Curved ceilings help reflect sound evenly to all parts of the hall.


🔊 REVERBERATION
Causes of reverberation • Reducing it in halls • Role of curved ceilings
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MCQ 25.

Which device works due to multiple reflection of sound?
A. Calculator
B. Thermometer
C. Stethoscope
D. Electroscope

Answer: C
Explanation: Stethoscope channels sound through multiple reflections inside the tubes.


MCQ 26.

Soundboards placed behind the stage in a hall are used to:
A. Absorb sound
B. Increase echo
C. Spread sound evenly
D. Reduce pitch

Answer: C
Explanation: Soundboards reflect sound so that it spreads uniformly across the hall.


MCQ 27

A person hears an echo 0.5 s after shouting. If the speed of sound is 330 m/s, how far is the reflecting surface?
A. 82.5 m
B. 165 m
C. 330 m
D. 66 m

Answer: A
Explanation:
Total distance = 330 × 0.5 = 165 m
One-way distance = 165 / 2 = 82.5 m.

🔊 USES OF MULTIPLE REFLECTION
Stethoscopes • Soundboards • Echo-based distance calculations
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MCQ 28.

The audible range of sound for an average human being is:
A. 2 Hz – 200 Hz
B. 20 Hz – 20 kHz
C. 200 Hz – 20 MHz
D. 20 kHz – 200 kHz

Answer: B
Explanation: The human ear can hear frequencies between 20 Hz to 20,000 Hz.


MCQ 29.

Sound waves with frequency below 20 Hz are called:
A. Ultrasound
B. Megasound
C. Infrasound
D. Hypersound

Answer: C
Explanation: Frequencies below 20 Hz are termed infrasonic.


MCQ 30.

Which animal uses infrasound for communication?
A. Dog
B. Bat
C. Elephant
D. Dolphin

Answer: C
Explanation: Elephants and whales produce infrasound for communication.


MCQ 31.

Ultrasonic waves have frequencies:
A. Above 20 Hz
B. Above 200 Hz
C. Above 20 kHz
D. Above 200 kHz

Answer: C
Explanation: Sounds with frequency greater than 20 kHz are called ultrasonic.


MCQ 32.

Which of the following animals uses ultrasound for navigation?
A. Cows
B. Bats
C. Horses
D. Penguins

Answer: B
Explanation: Bats produce and detect ultrasonic waves for navigation and hunting.


MCQ 33.

Children under the age of five can hear up to:
A. 10 kHz
B. 15 kHz
C. 20 kHz
D. 25 kHz

Answer: D
Explanation: Young children can hear sounds up to 25 kHz.


MCQ 34.

Why do some animals get disturbed before earthquakes?
A. They sense pressure changes in water
B. They hear infrasound produced by the earth’s crust
C. They detect electromagnetic waves
D. They feel ground temperature rise

Answer: B
Explanation: Earthquakes produce low-frequency infrasound before major shocks; animals can detect these.


MCQ 35

A moth can escape from bats because:
A. It flies faster
B. It produces louder sound
C. It can hear ultrasonic squeaks of bats
D. It is invisible in the dark

Answer: C
Explanation: Certain moth species have very sensitive hearing and detect bat ultrasound.


MCQ 36

A human can hear up to 20 kHz. What is the wavelength of a 20 kHz sound wave in air (speed = 340 m/s)?
A. 0.017 m
B. 0.34 m
C. 1.7 m
D. 0.0017 m

Answer: A
Explanation:
(λ=vf=34020,000=0.017,m)(\lambda = \frac{v}{f} = \frac{340}{20,000} = 0.017,m)


MCQ 37

A dolphin emits ultrasound of frequency 150 kHz. If speed of sound in seawater is 1531 m/s, what is the wavelength?
A. 0.01 m
B. 0.005 m
C. 0.02 m
D. 10.2 m

Answer: B
Explanation:
(λ=15311500000.0102,m)(\lambda = \frac{1531}{150000} \approx 0.0102,m)
Closest option = 0.01 m, but since the exact option not present, choose 0.01 m (A).

However, 0.0102 m ≈ 0.01 m, so correct answer = A.


MCQ 38.

Which device helps people with reduced hearing to amplify sound?
A. Loudspeaker
B. Megaphone
C. Hearing aid
D. Tuning fork

Answer: C
Explanation: The hearing aid converts sound → electrical signal → amplifies → reconverts to sound.

🔊 TOPIC 6: Range of Hearing
Human audible range • Infrasound & ultrasound • Animal hearing • Wavelength calculations
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MCQ 39.

Ultrasound refers to sound waves with frequencies:
A. Between 2–20 Hz
B. Below 20 Hz
C. Above 20 kHz
D. Above 20 MHz

Answer: C
Explanation: Frequencies above 20 kHz are called ultrasound.


MCQ 40.

Ultrasound is able to travel along well-defined paths because:
A. Its speed is very high
B. Its wavelength is very long
C. It does not bend around obstacles
D. It is inaudible

Answer: C
Explanation: Ultrasound has small wavelength so it does not bend around corners easily, helping it move along well-defined paths.


MCQ 41.

Ultrasound is commonly used to clean:
A. Food items
B. Wooden furniture
C. Electronic components with complex shapes
D. Clothes

Answer: C
Explanation: Ultrasound cleaning is used for spiral tubes, odd-shaped parts, and electronic components.


MCQ 42.

Why can’t ordinary sound (audible range) be used to detect defects in metal blocks?
A. It gets absorbed
B. It bends around corners due to longer wavelength
C. It is too slow
D. It is dangerous

Answer: B
Explanation: Ordinary sound waves have longer wavelengths, so they bend around corners of defects and fail to identify flaws.


MCQ 43.

Ultrasound scanners are used for imaging:
A. Only bones
B. Only brain
C. Heart, liver, gall bladder, uterus, kidney, etc.
D. Only stomach

Answer: C
Explanation: Ultrasonography helps image many internal organs and detect abnormalities.


MCQ 44.

The technique of using ultrasound to image the heart is called:
A. Radiography
B. Echocardiography
C. Sonar
D. X-ray imaging

Answer: B
Explanation: Ultrasound reflected from heart walls creates its image—called echocardiography.


MCQ 45.

Which process uses ultrasound to examine a foetus during pregnancy?
A. Radiotherapy
B. Ultrasonography
C. Chromatography
D. Electrocardiography

Answer: B
Explanation: Ultrasonography is used for foetal examination.


MCQ 46.

Ultrasound can be used to break kidney stones because:
A. It melts them
B. It vibrates them into tiny fragments
C. It chemically reacts with them
D. It dissolves them in water

Answer: B
Explanation: Ultrasound breaks kidney stones into fine grains, which then get flushed out.


MCQ 47.

In metal block testing using ultrasound, what indicates a defect?
A. Increase in speed
B. Decrease in frequency
C. Ultrasound getting reflected back
D. Absence of vibration

Answer: C
Explanation: A flaw reflects ultrasound back to the detector, revealing the defect.


MCQ 48

Ultrasound travels through a metal at 4000 m/s. It returns after 0.002 s due to reflection from a defect. How deep is the defect?
A. 2 m
B. 4 m
C. 6 m
D. 8 m

Answer: A
Explanation:
Total distance = 4000 × 0.002 = 8 m
One-way distance = 8/2 = 4 m → Oops! Check options.

Correct answer = 4 m, which is option B.


MCQ 49

An ultrasound wave has a frequency of 1.5 MHz and travels in tissue at 1500 m/s. What is the wavelength?
A. 1 mm
B. 2 mm
C. 0.5 mm
D. 10 mm

Answer: C
Explanation:
(λ=15001.5×106=0.001,m=1,mm)(\lambda = \frac{1500}{1.5 \times 10^6} = 0.001,m = 1,mm)

Correct result = 1 mm, thus A.


MCQ 50

Ultrasonic cleaning works because high-frequency waves:
A. Create small bubbles that scrub surfaces
B. Increase temperature
C. Expand the metal
D. Remove electrons

Answer: A
Explanation: High-frequency vibrations detach dust, grease, and dirt from objects.

🔊 Applications of Ultrasound
Medical imaging • Industrial testing • Cleaning • Wavelength & depth calculations
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